Mercury has a density of 13.6 g/mL. If I want to gather 175 g of the metal, what volume of mercury would I need?

Let's break the answer down into three parts: $color (brown) ("First,"$ we're going to convert grams to pounds using this conversion factor: $color(white)(aaaaaaaaaaaaaaaaa$ 1 pound = 453.592 grams $color (purple)...

There are $0.454*lb*(kg^-1)$ so $2.203*kg*(lb^-1)$, and $1*cm^3 = 1*mL$ So we just do the conversion: $5.0*cancel(L)xx1000*cancel(cm^3)cancel(L^-1)xx13.6*g*cancel(cm^-3)$ $=$ $??g$; ; $??cancel(g)xx10^(-3)cancel(kg)*cancel(g^-1)xx(2.203)lb*cancel(kg^-1)$ $=$ $??$ $lb$

We need to (i) find the volume of mercury; and (ii) convert this volume into a mass by use of the quoted . $"Volume of mercury"$ $=$ $76.0*cmxxpixx(0.5*cm)^2$ $=$ $59.7$...

For a given substance, its tells you the mass occupied by one unit of volume of that substance. In essence, is a measure of how well the molecules of...

the mass of $1ml$ is $13.6gm$ $:.$the mass of $45ml$ is=$(13.6xx45)$gm $=612gm$

A substance's basically tells you how much mass of said substance occupies one unit of volume. In your case, the of mercury is given in Grams per milliliter,...

The density, $rho$, of mercury $=$ $13,593*kg*m^-3$; it is $13.6*g*cm^-3$ in more accessible units. Anyway, mercury metal is pretty dense stuff. If you ever found a pool of mercury, you...

By definition, $rho_"metal"="mass of metal"/"volume of metal"$ $=(800*g)/(33.0*cmxx46.0*cmxx48.0*cm)=0.0659*g*cm^-3$ And this is an IMPROBABLY undense metal. The LEAST dense metal, lithium, is approx. $0.5*g*cm^-3$...(at any rate this metal reacts with water)...the...

$"Density,"$ $rho$ $=$ $"Mass"/"Volume"$. And thus, $"Volume"$ $=$ $"Mass"/rho=(7.6*g)/(13.6*g*mL^-1)$. This is dimensionally consistent as $cancelg/(cancelg*mL^-1)$ $=1/(mL^-1)=1/(1/(mL))=mL$, and thus we get an answer with units of volume as required.

Ionic bonds occur between anions and cations. And cations may be metallic, i.e., $M^(2+)$, or they may be non-metallic, i.e. ammonium salts, $NH_4^+$. And anions, while typically non-metallic, i.e. $X^-$...