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A substance's basically tells you how much mass of said substance occupies one unit of volume.

In your case, the of mercury is given in Grams per milliliter, $"g mL"^(-1)$, which means that it expresses the mass of mercury in $"1 mL"$ of mercury.

So, mercury is said to have a density of $"13.534 g mL"^(-1)$, which means that $"1 mL"$ of mercury has a mass of $"13.534 g"$.

You want to know the volume of mercury that will contain $"10.0 g"$ of the element. Since your sample is lighter than the mass associated with $"1 mL"$, you can expect its volume to be smaller than $"1 mL"$.

You can use dimensional analysis using the density of mercury as a conversion factor

$10.0color(red)(cancel(color(black)("g"))) * overbrace("1 mL"/(13.534color(red)(cancel(color(black)("g")))))^(color(purple)("given density")) = color(green)(|bar(ul("0.739 mL"))|)$

The answer is rounded to three **, the number of sig figs you have for the mass of your sample.

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