A rectangular prism of volume $84$ $cm^3$ has a mass of $760$ $g$. What is the density of the rectangular prism?

Dimensions of the rectangular prism Width = w Height = h Length = l surface area (S) = $2*h*l + 2*h*w+2*l*w$ volume (V) = $h*l*w$ = $S/V$ = $(2(h*l+h*w+l*w))/(h*l*w)$...

Before doing any calculation, try to predict what you should see happen to the of the gas. Under the initial conditions for pressure and temperature, the oxygen gas had...

For a given substance, its tells you the mass occupied by one unit of volume of that substance. In essence, is a measure of how well the molecules of...

$"Density"$ $=$ $"Mass"/"Volume"$ Thus $"Mass"$ $=$ $"Density"(rho)xx"volume"$ $"Mass of silver"$ $=$ $10.5*g*cancel(cm^-3)xx5*cancel(cm^3)$ $=$ $52.5*g$. $"Mass of gold"$ $=$ $19.3*g*cancel(cm^-3)xx5*cancel(cm^3)$ $~=$ $100*g$. Note that I solved this problem dimensionally. I wanted...

$rho="Mass"/"Volume"=(16*g)/(8*cm^-3)$ $=$ $??*g*cm^-3$ And the volume of each piece is $??*cm^3$.

So....... $"Volume"$ $=(15.3*cmxx9.0*cmxx4.5*cm)$ $=$ $??cm^3$ We know we can't be too wrong, because our calculation gave us units in $cm^3$, i.e. in the units of volume as required.

You know that the sample is shaped as a rectangular cube, i.e. a rectangular prism, which means that you can determine its volume by using the equation $color(blue)(ul(color(black)(V...

The mass we are given in grams......we convert all the dimensions into $cm$, to give an answer in $rho=g*cm^-3$.....which is a common unit of for chemists.......... $rho=(16.04*g)/(1.26*cmxx3.30*cmxx1.40*cm)$ $=2.76*g*cm^-3$. Do you...

We're asked to find the of the rock, given some mass and volume information. We're given that the mass of the system before the rock was added was...

The first thing that you need to do here is to figure out the volume of the sample by using the fact that you're dealing with a rectangular prism, which...