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How many chromosomes are in a sperm cell from an animal whose somatic cells have 32 chromosomes (2n=32)? If 2n=32, how many chromosomes are in a haploid cell?
So in an animal with 32 (2n) chromosomes in somatic cell, number of chromosomes in sperm will be 16 (n).
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What is the volume of $150.0*"gallons"$ in $"litres"$?
So to the calculation: $(150.0cancel" gallons" xx 4.8*cancelL*cancel("gallon"^-1))/(25.0xx10^-3*cancelL)$ $= ??$ I get a large dimensionless number. I have used an Imperial gallon here (equivalent to $8$ $"pints"$, $4800$ $mL$). A...
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9. The density of water is 1.0 g/mL. What is the density of water in pounds/gallon?
Use "Dimensional Analysis" to determine what "conversion factors" you will need before you do the math. $g/"mL" xx "??"/"??" = "lbs"/"gal"$ We need a mass conversion unit ($g to "lbs"$)...
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What volume in litres is equivalent to $5.88*dL$?
And thus $5.88$ $dL$ $=$ $5.88$ $cancel(dL)$ $xx10^-1*L*cancel(dL^-1)$ $=$ $0.588*L$
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What are the relationships between $"microliters"$, $"millilitres"$, $"litres"$, and $"cubic centimetres"$?
And $"1 millilitre"-=10^-3*L$.... And $"1 litre"-=10^-3*m^3$.. And $"1 cubic centimetre"=(10^-2*m)^3=10^-6*m^3$ $=1/1000xx1/1000*m^3=10^-3*L=1*mL$... I think you should try your hand at the other conversions...they do make sense, and are logical and straightforward....
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What volume of water in LITRES is contained in a dam whose area was $18.9*"mile"^2$, and whose average depth was $47*ft$?
We gots .................. $18.9*"mile"^2-=18.9*"mile"^2xx2.59xx10^6*m^2*"mile"^-2"$ $=49.0xx10^6*m^2$ $(i)$ And average depth is $47*ftxx0.3048*m*ft^-1=14.3*m$ $(ii)$ And $"volume"=(i)xx(ii)=49.0xx10^6*m^2xx14.3*m=$ $=702xx10^6*m^3$. And we know that there are $10^3*L*m^-3$ And so we got $702xx10^6*m^3xx1000*L*m^-3-=702xx10^9*L$. An acquaintance of...
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Chemical reaction of octane burning: $2C_8H_18 + 25O_2 -> 18H_2O + 16CO_2$. Octane has a density of 703.00 kg/$m^3$, or 703.00 g/L. A gallon is 3.78541 L. What is the mass (in g) of 1.0000 gallon of octane?
Keeping track of the units as you go through this calculation will guarantee that you get it right. $703.00 (kg)/m^3xx1000g/(kg)xx1/1000m^3/Lxx3.78541L/(gal)$ Note that after the first value, each remaining number is...
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Home barbeques are fueled with propane gas (C_3H_8). What mass of carbon dioxide (in kg) forms upon the complete combustion of 18.9 propane (approximate contents of one 5-gallon tank)?
We address the combustion equation.. $H_3C-CH_2CH_3(g) + 5O_2(g) rarr 3CO_2(g) +4H_2O(l) + Delta$ And, assuming you are a septic, $"1 US Gallon"-=3.785*L$.. We combust a mass of ethane... $"5 US"...
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How many particle or molecules of $Na_2CO_3$ are produced when 10g of $NaOH$ is used? $22.3 x 10^24$ particles of $NaOH$ are needed to produce how many liters of $H_2O$? How many particles/molecules of $NaOH$ are from 30 gram of $NaOH$?
$2NaOH(s) + CO_2(g) -> Na_2CO_3(s) + H_2O(l)$ Molar mass of $NaOH = 40 $ $2xx40 g$ of $NaOH$ produces $6.02 xx 10^23$ molecules of $Na_2CO_3$ $:.$ $10 g$ of $NaOH$...
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How I can calculate the number of hydrogen atoms in one gallon deionized water? thank you so much.
Step 1. Convert gallons of water to litres $"Volume" = 1 color(red)(cancel(color(black)("gal"))) × "4.55 L"/(1 color(red)(cancel(color(black)("gal")))) = "4.55 L"$ Step 2. Convert litres of water to grams of water...
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