This problem can be solve using the formula shown below.
$%"error"="absolute error"/"actual value"xx100$
$where:$
$"absolute error"="actual value"-"experimental value"$
$"absolute error"=(185cal)/(g*^oC)-(156cal)/(g*^oC)$
$"absolute error"=(29cal)/(g*^oC)$
Knowing the absolute error, % error can be calculated using the formula described above. Plug in the given and the calculated values as shown below.
$%"error"="absolute error"/"actual percentage"xx100$
$%"error"=(29cancel((cal)/(g*^oC)))/(185cancel((cal)/(g*^oC)))xx100$
$%"error"=0.16xx100$
$%"error"=16%$