The percent error is basically the fractional deviation from the accepted value.
The percent error is the absolute difference between the measured/approximate and accepted/exact values, relative to the exact value:
$\mathbf(% "Error" = |"Approximate" - "Exact"|/("Exact")xx100%)$
$= |82 - 80|/(80)xx100%$
$= color(blue)(2.5%)$
So the percent error is
The dimension of Hubble constant, $[H_o]-LL^(-1)T^(-1)=T^(-1)$. The dimension of thr reciprocal $[1/H_o]=T$ As of now, different estimates of $H_o$ have a range around 70 km/s/mega parsec. The reciprocal, after unit...
1 Answers 1 viewsPercent error is defined as the difference between the experimental value and the theoretical value, taken in absolute value, divided by the theoretical value, and multiplied by $100$ $color(blue)("%...
1 Answers 1 viewsPercent error and percent deviation are the same thing. They both measure the relative error when you compare the results you got (the experimental/measured results) and compare them to the...
1 Answers 1 viewsThe accepted value is a number or value that scientists and the public regard as true. The experimental value is the value that you get in an experiment. The absolute...
1 Answers 1 viewsThe formula for percent error is: % error = $(x_(measured)-x_(true))/x_(true)*100%$ Our $x_(true)$ value is 5.5 m. All we do now is solve for % error by plugging in each result....
1 Answers 1 viewsThe formula for percent error is Percent error$=abs((E-T)/T) * 100$ where E = experimental value and T= theoretical or accepted value Percent error $=abs((2.04-2.00)/2.00) * 100$ $=abs(.04/2.00) * 100...
1 Answers 1 viewsYou have to compare the of $"CO"_2$ produced experimentally at STP to the accepted density of $"CO"_2$ at STP. $"density"="mass"/"volume"$ You are given the mass and volume of the experimentally...
1 Answers 1 viewsPercent error $= 100times(Actual-Measured)/(Actual)$ You can compute percent error now: Percent error $= 100times(17.9-17.4)/17.9$ Percent error $= 100times0.5/17.9 = 50/17.9 = 2.79$ Percent error is 2.79.
1 Answers 1 viewsThis problem can be solve using the formula shown below. $%"error"="absolute error"/"actual value"xx100$ $where:$ $"absolute error"="actual value"-"experimental value"$ $"absolute error"=(185cal)/(g*^oC)-(156cal)/(g*^oC)$ $"absolute error"=(29cal)/(g*^oC)$ Knowing the...
1 Answers 1 viewsBased on the information I got from you: $m_"Zn" = "6.530 g"$ $m_("CuSO"_4cdot5"H"_2"O") = "5.00 g"$ (in lab you tend to be handed the hydrate) From the molar...
1 Answers 1 views