How do you convert 325 Joules to Calories?

Calories per gram ($"Cal/g"$) implies calories per gram associated with those calories. A change-in-food mass is associated with the $"Cal/g"$ units, and just like a change in position in $"m"$...

You have 960 J in that many calories. To go from calories to Joules, or vice versa, use the fact that 1 calorie is equivalent to 4.184 J. Use...

So, $148 " calories"xx4.1854 " Joule calorie"^-1$ $=$ $??$ $"Joule"$

So, we do the conversion: $500cancel" Calorie"$ $xx$ $4.1854$ $J*cancel"calorie"^-1$ $=$ $?? J$

It is important to realize that when the term 'nutritional calorie' is used, they mean kilocalorie (= $1000$ calories). It is known that 1 calorie is approximately $4.184$ Joules....

We know (or should know) that $n=(PV)/(RT)$, and further that $1*atm-=760*mm*Hg$. And thus $n=((785*mm*Hg)/(760*mm*Hg*atm^-1)xx325*L)/(0.0821*L*atm*K^-1*mol^-1xx305*K)~=13*mol$. And $13*molxx44.0*g*mol^-1~=600*g$. From where did I get the figure $44.0*g*mol^-1$? My own feeling is that you...

By definition, $"1 cal"$ is the approximate amount of energy needed to raise the temperature of $"1 g"$ of water by $1^@ "C"$ at $"1 atm"$. In thermochemistry, this...

How to convert 1 kilocalorie (kcal) to calories (cal). 1 small kilocalorie (kcal) is equal to 1 large food calorie (Cal): 1 kcal = 1 Cal 1 small kilocalorie (kcal)...

$"1 calorie"-=4.184*"Joule"$ And thus.....$1.41*kcal-=1.41xx10^3*calxx4.184*J*cal^-1$ $=5899.4*J-=5.90*kJ$....

To identify the independent and dependent variables you need to first identify what the variables are. Then you ask yourself, which variable will be affected if anything is changed? For...