Its visual magnitude is about 11.0
1 Answers 1 viewsNext nearest star is proxima century 4 .3. light years away. Sun is one A U away from Earth.149597870 KM.
1 Answers 1 views1 light year = 5.88 E+12 miles. So, at 2000 mph, the time to reach Alpha Centauri is 4 X 5.88E+12/2000 hours = 1.176E+10 hours = 1.176E+10/(24 X 365.256) years...
1 Answers 1 viewsThe difference between Earth and Sun is only 8.2 light minutes. So it does not matter whether it is Sun or Earth. The distance 4.243 light years is 2230120 light...
1 Answers 1 viewsAlpha Centauri is the nearest star as far as present knowledge allows. So the distance to Alpha Centauri is 25700 000 000 000 Putting this value into scientific notation involves...
1 Answers 1 views$1ly~~5.8786*10^12mi$ Therefore, $4.3ly~~4.3(5.8786*10^12)=2.5278*10^13mi$
1 Answers 1 viewsLighttravels 300000 kilometers inone second
1 Answers 1 viewsThe average speed is $(4.12 E+16)/(1.73 E+10)$ meter/s =2.38 E+03 km/s. The distance of Alpha Centauri is about 4.3 light years= 2.7 E+05 AU = 4.05 E+13 km. The time...
1 Answers 1 viewsThe Oort Cloud is an extended shell of icy objects that exist in the outermost reaches of the solar system. It is named after astronomer Jan Oort, who first theorised...
1 Answers 1 views$(1/2)^(t/5730)(I)=A$ I = initial amount, A = current amount, t = years I=0.200g, A= 0.0125g, solve for t $(1/2)^(t/5730)(0.200)=0.0125$ $(1/2)^(t/5730)=0.625$ $log_(1/2)((1/2)^(t/5730))=log_(1/2)0.0625$ $t/5730=4$ $t=22920$
1 Answers 1 views