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how many milliliters of a 10.0% saline solution are needed to make 500 mL of 0.9% saline solution?
Let V ml of a 10.0% saline solution is consider .So , v* 10 / 100 is the mass of solute .------------------- 1 .To Make Solution of 500 mL of...
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An aqueous solution has 18% of solute. By chemical analysis, it was known that it has 10 mol% solute.
What is the molecular weight of the solute?
m = n*M, m - weight, n - quantity of substance, M - molecular weight mx /18 = mH2O / 82nx = nH2O / 9nx *Mx = nH2O * MH2O*18/82Mx...
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A physician has ordered 0.64 of atropine, intramuscularly. If atropine were available as 0.10 of solution, how many milliliters would you need to give?
Answer is 6 portions (0.60), because we use the rounding to the nearest integer and numbers that are less than 4 should round to 0.
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how mole fraction is to use distinguished between solute and solvent in a solution when contain equal amount of solute and solvent
solute and solvent in a solution when contain equal amount of solute and solvent .then Both Have Equal Mass .let mass of solute and solvent both have " W "...
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A solution in which the dissolved solute and undissolved solute are in equilibrium is?
Is saturated solution
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A plant cell with 5% solute and 95% water is placed into a solution of 10% solute and 90% water. The solution is _____ then, water will move _____.
The solution is hypertonic then, water will move out of the cell.
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How many milliliters of a 0.339 M hydrochloric acid solution are required to neutralize 23.3 mL of a 0.668 M barium hydroxide solution?
С(HCl) = 0.339 M V(Ba(OH)2) = 23.3 mL C(Ba(OH)2) = 0.668 M V(HCl) -? 2HCl + Ba(OH)2 => BaCl2 + 2H2O ν(Ba(OH)2) = C(Ba(OH)2)* V(Ba(OH)2) = 0.668 M*0.0233 L =...
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82 mg of solute is mixed into a 0.35 L solution. At a temperature of 37°C and an osmotic pressure of 3.2 x 10-3 atm, calculate the molar mass of the solute.
82 x 0.082 x 310/1000 x 3.2 x 10-3 x 0.35 = 1,861.10714
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How much 2.0 % salt solution can be made to fill the bags of a hospital if 16.7 of salt are available ?
A. 835 solution
B. 334 solution
C. 0.334 solution
D. 835000 g solution
16.7 g of salt are available16.7 * 100 / 2 = 835 g - solution massAnswer A
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How many milliliters of 0.7800M LiBr can be made if 125.0 g of LiBr are dissolved?
1mol = 86.845 g ? = 125g (125g)/(86.845g)= 1.4733moles 1.4733 = 125g0.7800moles = ? Therefore ( (0.7800)(125))/ 1.4733=66.18g1g = 1 millitre 66.18g = (66.18)(1) = 66.18 Ml
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