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Calculate the cell potential of the following cell at 298K.
Zn(s)|Zn^2+(0.6 M)||Cu^2+(0.3 M)|Cu(s)
E0 (Zn^2+| Zn) = -0.76 volt, E0(Cu^2+ |Cu) =0.34 volt.
Cell notation = anode||cathode (oxidation||reduction) Zn(s) ------gt; Zn2+ + 2e- Eo = -0.76 V Cu2+ + 2e- --------gt; Cu Eo = 0.34 V Eo = 0.76 + 0.34 = 1.1...
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Calculate the concentration of OH- ions when reacting with 100 cm3 of KOH solution, concentration 0.09 mol / dm3 with 120 cm3 of H2SO4 solution with concentration 0.1 mol / dm3!
The reaction given:2KOH + H2SO4 = K2SO4 + 2H2OAs 1 L = 1dm3 and 1 ml = 1 cm3, the number of moles of the reactants equals:n(KOH) = M × V = 0.09...
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What is the concentration (in mol / dm3) of KCl in the solution formed by mixing 25 mL of KCl solution, 0.100 M concentration with 50 mL of KCl solution, 0.100 M concentration?
The concentration of both solutions is equal. Therefore, we will get 75 ml of 0.100 M KCl solution.0.100 M = 0.100 mol/dm3.
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What are the conversation factors for the equality 1 meter = 100 centimeters?
a. 1 m /100 cm and 100 cm/1m
b.1 m/100 cm
c. 1 cm/100 m and 100 m/1 cm
d. 1 m/1000 cm and 1000 cm/1 m
Solutions: Meters (m) and centimeters (cm) can be related by the prefix modifier equality 100 cm = 1 m.So therefore, this equality given above can be represented as two conversion...
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Write the overall cell potential and calculate the standard cell potential of the following and balance the equation. Ag⁺ + e → Ag E⁰ = 0.80 V Mn⁺² + 2e → Mn E⁰ = -1.18 V
E=E0(Ag)−E0(Mn)=0.80−(−1.18)=1.98VAnodeMnMn−2e=Mn+2(+)CathodeAgAg++1e=Ag(−)
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National Income Accounts.
X 100. Transfers 100. PIT 220.
SST 60. IBT1 40. NPI 40. I 100.
CRE 20. C 700. NFFI 100. Depreciation 60.
IBT2 40. G 300. M 200.
Determine DP
The DP is defined as follows: DP =C+G+I+(X-M) DP =700 + 300 + 100 + (100-200) = 1000
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National Income Accounts.
X 100. Transfers 100. PIT 220. SST 60.
IBT1 40. NPI 40. I 100. CRE 20. C 700.
NFFI 100. Depreciation 60. IBT2 40. G 300. M 200.
Determine PI.
The personal income is defined as follows: PI= NI+transfers+NPI-CRE-SST-IBT2 Where NI =GNP-depreciation-IBT1 GNP=GDP+NFFI=C+I+G+(X-M)+NFFI GNP = 700 + 100 + 300 + (100-200) +100 =1100 NI =1100 – 60 – 40...
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National Income Accounts.
X 100. Transfers 100. PIT 220. SST 60.
IBT1 40. NPI 40. I 100. CRE 20. C 700.
NFFI 100. Depreciation 60. IBT2 40. G 300. M 200.
Determine NI
The national income is defined as follows: NI =GNP-depreciation-IBT1 Where GNP=GDP+NFFI=C+I+G+(X-M)+NFFI GNP = 700 + 100 + 300 + (100-200) +100 =1100 NI =1100 – 60 – 40 =1000
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National Income Accounts.
X 100. Transfers 100. PIT 220. SST 60.
IBT1 40. NPI 40. I 100. CRE 20. C 700.
NFFI 100. Depreciation 60. IBT2 40. G 300. M 200.
Determine GNP.
The gross national product is defined as follows: GNP=GDP+NFFI GDP=C+I+G+(X-M) GDP = 700 + 100 + 300 + (100-200) =1000 GNP=1000+100=1100
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consider the following economy, where prices are fixed: c=100+3/4*( disposable income, t= 1/3*y , i=100, g=300, x=100, m=1/6*y. what is the equation for the aggregate expenditure curve?
Solution:The equation for aggregate expenditure curve is: AE = C + I + G + NXWhere: C = Consumption I = Investment G = Government spending NX = Net Exports (Exports – Imports)T...
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