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CaCO3 + 2HCl → CaCl2 + CO2 + H2O

Mg(OH)2 + 2HCl → MgCl2 + 2H2O

M(CaCO3) = 100 g/mol

M(Mg(OH)2) = 56 g/mol

Two moles of HCl are used for one mole of antacid product in both reactions.

So, to neutralize of two moles of HCl less Mg(OH)2 (56 g) are required as compared to 100 g of CaCO3.

So, milk magnesia is more effective at neutralizing acid per gram of the active ingredient.

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