Ammonia and oxygen react to form nitrogen monoxide and water. Construct your own balanced equation to determine the amount of NO and H2O that would form when 2.08 mol of NH3 6.32 mol of O2 react

Md Ariful Islam

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4NH3+5O2---->4NO+6H2O

2.08 moles of ammonia will require 2.6 moles of oxygen gass from the mole ratio of 4:5 the ratio of ammonia to oxygen.

(2.08÷4)×5=2.6

This implies that ammonia is the limiting reagent and oxygen is in excess.

Consequently, the output of NO depends on the limiting reagent which is ammonia in this case.

4NH3:4NO

The ratio is 4:4.

To find moles of NO produced;

(2.08÷4)×4=2.08 moles.

The reaction produces 2.08 moles of NO, the volume depends on the temperature and pressure of the experiment

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