Consider a container with 5.08g of N2 gas and an unknown mass of CO2 gas. If we know that the partial pressure of the CO2 is twice that of the N2, determine the mass of CO2 gas in the container

Md Ariful Islam

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Md Ariful Islam

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Mass of nitrogen= 5.08 g

No.of mole of nitrogen= 5.08/28

= .182

Partial pressed of nitrogen let = P

PV=nRT

V=.182RT/P

In case of carbon dioxide

Mass of carbon dioxide=?

Partial pressure of carbon dioxide= 2P

PV=nRT

n=PV/RT

n=2P×.182RT/PRT

n=.364

Mass of carbon dioxide in container is

=.364×44

=16 g

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