In 25 grams of a 7.5% by mass solutions of CaSO4 1.) how many grams of solute are present 2.) how many grams of solvent are present

Md Ariful Islam

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Solution

1.Wt. Of solute in gm. = (25*7.5)/100

= 1.875 gm.

2. Since wt. of solution = wt. of solute + wt. of solvent

Wt. of solution = 100 gm.

Wt. of solvent in gm. = 100 - 1.875

=98.125 gm.

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