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C1(NaOH) = 19 M;

C2(NaOH) = 0.25 M;

V1 = 2 ml;

V2 = unknown.

Proportion 1:

19 moles — 1000 ml

x moles — 2 ml

x = 0.038 moles in 2 ml of 19 M NaOH;

Proportion 2:

0.25 moles — 1000 (ml)

0.038 moles — y (ml)

y = 152 ml (final volume of the solution);

V(H2O) = 152 ml — 2 ml = 150 ml;

Answer: V(H2O) = 150 ml; V(final) = 152 ml

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