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the energy required to remove two valence electrons of a metalic atom is called?
a)ionization energy
b)second ionization energy
c)activation energy
d)electron potential
An answer is a) ionization energy .
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When alkali metals are heated with Hydrogen they form ------ hydryide
a) non-stoichiome try b) covalent c) Ionic d) metalic
C) ionic
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A solution is made containing 14.8 g of CH3OH in 186 g H2O. Calculate the mass percent of CH3OH.
As we know thattotal mass of solution (mtotal) = weight or mass of H2O (mH2O) + weight or mass of CH3OH (mCH3OH)total mass of solution (mtotal) = 186 g + 14.8...
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in a aquas solution of concentrate HBr acid , HBr is 48% of total mass.if its density is 1.50gram per ml then what is the value of its concentration?
Solution M(HBr)=80.917 g/mol. The concentration is (1000mL/L)(1.5 g/mL)(0.48)(1/(80.917 g/mol))=8.9 mol/L. Answer: 8.9 mol/L.
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Discuss the validity of the statement “All polar bonds molecules must have polar bonds and all non polar molecules must have non polar bonds.”
The statement is correct.
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why do all polar bonds molecules have polar bonds and all non-polar molecules have non-polar bonds?
Nonpolar bonds form between two nonmetals with the same electronegativity value. Nonpolar molecules may contain any type of chemical bonds, but the partial charges cancel each other out.Polar bonds form...
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Estimate ΔH for the reaction using bond dissociation energies from Table 7.1. Give your answer in kcal. C6H12O6 has five C−C bonds, seven C−H bonds, seven C−O bonds, and five O−H bonds.
Answer: Reaction is absent All that I can tell about answer is ΔH= ΔERECTANTS BONDS – ΔE PRODUCTS BONDS
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Calculate the volume (in mL) of a 0.235 M HBr solution that would react with 0.362 g KOH according to the equation,
HBr + KOH → KBr + H2O
1) m(KOH) = 0,362g CM = n/V; V = n/CM n(KOH) = m/M = 0,362g /56g/mol = CM(HBr) = 0,235 M =0,00646 mol; n(HBr) =0,00646 mol ; V(HBr) - ? V(HBr) = 0,00646...
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What is the percent yield of the following reaction if 3.50 g of CO2 were produced from the reaction of 10.0 g of CaCO3 with excess HBr?
CaCO3 (s) +2 HBr (aq) → CaBr2 (aq) + H2O (l) + CO2 (g)
79.5%
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Why do some materials have both polar and non-polar properties? How are these mixed properties of molecules applied in industry and household?
Materials have both polar and non polar properties because they are amphiphilic ( they have both hydrophobic and hydrophilic groups)They are mostly used in the production of organic solvents
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