Question #3 The n to pi star in acetone occur at longer wavelength than the pi to pi star transition, yet the latter transition has a much higher molar absorptivity. Explain.

Md Ariful Islam

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Md Ariful Islam

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This is because the lone pair interacts with the solvent such that the solvent align itself with ground state thus lowering energy at ground state and not at excited state.

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Acetone, the solvent in many nail polish removers, has a density of 0.791 g/mL. What is the volume, in mL, of 74.7 g of acetone?

V=m/r=74.7/0.791=94.4 mL

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The vapour pressure of acetone at 56.5 °C is 760 mmHg. What will be its vapour pressure at 25 °C if the heat of vaporization of acetone is 32.0 kJ/mol (Given R=8.314 J/Kmol).

Vapour pressure at 25°C=987mmHg

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A solution contains 20.0g of NaCl in 750ml distilled water is found to have an absorbance of 2:52 at 520nm when the path length is 1cm. Calculate the molar absorptivity with units.

Molar mass of NaCl= 58.4420/58.44= 0.342750/1000= 0.75Molarity= 0.342/0.75= 0.456mol/L0.456×520= 237.28

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<ul><li>Explain the following items : (1) Absorbance. (2) Transmittance. (3) absorptivity. </li></ul>

(1) Absorbance is the logarithm of the ratio of incident to transmitted radiant power through a sample (excluding the effects on cell walls).(2) Transmittance is a measure of the amount...

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What is the mass, in grams, of 28.46 mL of acetone? Acetone (nail polish remover) has a density of 0.7857 g/cm3.

r = m/V m = V*r V = 28.46 ml = 28.46 cm^3 m = 28.46*0.7857 = 22.36 g Answer: 22.36 g

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what is the mass, in grams, of 28.80 mL of acetone? acetone has a density of 0.7857 g/cm^3.

m(acet) = 28.8ml*0.7857g/cm^3=22.6282g ml=cm^3

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A bottle of acetone (fingernail polish remover) contains 43.5 mL of acetone with a mass of 55.0 g. Express the density in grams per milliliter to three significant figures.

Solution. p= m/V= 1.264 (g/ml)Answer. 1.26 g/ml

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The standard (1 bar) boiling point of acetone is 56.1 C, and its enthalpy of vaporization is 29.1 kJ/mol. Calculate the vapor pressure of acetone at 43.5 C.

ln(p2 / p1)=- (∆Hvap/R) x (1/T2 - 1/T1)ln(p2/1)= -(29.1/8.314) x (1/329.25 - 1/316.65)p2=1.000423 bar

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Pure acetone has a vapor pressure P° = 30 kPa. A solution of water in acetone has a vapor pressure of 28.2 kPa. What is the mole fraction of water in this solution?

Psolution = xsolventPsolventxsolvent= Psolution/Psolvent= 28.2/30= 0.94.94%

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9. To be considered part of M3, deposits need to be held: a) longer than 5 years. b) longer than 6 months. c) longer than 30 days. d) All of the above. which one is correct?

a) longer than 5 years.

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