325.0787381N(t)= N(o)(1/2)^t/t1/2Where N(t) = Remaining massN(o) =Original massT =TimeT1/2 = Half lifeN(t) = 1800(1/2)^20/8.1= 1800(0.5)^20/8.1=325.0787381 grams
1 Answers 1 viewsIf we start with 100% of a sample , we can keep dividing this number by 2 until we reach 12.5% to find out how many half lives passed.Remember, when the sample...
1 Answers 1 viewsa) 87.5 Radb) 43.75 Radc) 5.46 Rad
1 Answers 1 viewsYou would need 1.5 ml to get atotal of 3 mCi I131 Stock solution contains 2.0 mCi/ml * X ml = 3.0 mCi X= 3.0/2.0 X= 1.5 ml
1 Answers 1 views9 × 24 = 216hours3hr =25mCi216= ?= 216× 25/3= 1800mCi
1 Answers 1 viewsTherequired time is 0.334*10 = 3.34 seconds.
1 Answers 1 views17g
1 Answers 1 viewsThe radioactivity changes according to this equasion: A=A0/2n; A0 - initial radioactivity;A - radioactivity after it undergoes n half-life decaya) A=175/2=87.5 Rad;b)A=175/22=175/4=43.75 Rad;c)A=175/25=175/32=5.47 Rad;
1 Answers 1 viewsa) 87.5 Radb) 43.75 Radc) 5.46 Rad
1 Answers 1 viewsa) 87.5 Radb) 43.75 Radc) 5.46 Rad
1 Answers 1 views