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The standard enthalpy of the reaction: CO(NH2)24) + H20) -› CO2(g) + 2 NHa(a) is -133.42 kJ/mol. Calculate the standard enthalpy of formation of urea, CO(NH2)2(6).
Standard enthalpy of formation=-362kJ/mol
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the standard enthalpy of formation of urea, CO(NH2)2(6). The standard enthalpy of the reaction: CO(NH2)2() + H2Om) -› COz) + 2 NHare) is -133.42 kJ/mol. Calculate
Standard enthalpy of formation=-362kJ/mol
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Define standard enthalpy of formation of a reaction. Write the reaction for the standard enthalpy of formation of C6H12O6
The standard enthalpy of formation is the change in enthalpy that accompanies the formation of one mole of the compound from its elements. The standard enthalpy of reaction occurs in a...
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the standard enthalpy of combustion of ethane, carbon, and hydrogen are -1559.7 kJ/mol, -393kJ/mol and -286kJ/mol respectively.
Use Hess'ss law to find the enthalpy of formation of ethane
ΔHform(C2H6)=ΔHcomb(C2H6)-(2ΔHcomb(C)+3ΔHcomb(H2))=-1559.7-(2(-393)+3(-286))=84,3 kJ/mol
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Define enthalpy of combustion. Calculate the enthalpy of combustion of methanol if the enthalpies of formation of CO2,H20 andCH3OH are respectively .
-393.5kj/mol,-285.8kj/mol and -239.0kj/mol.
Answer: Enthalpy of combustion is the heat released during combustion of one mol amount of any substance by oxygen.You can calculate the combustion enthalpy of methanol using the enthalpy...
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The enthalpy of formation of NH<sub>3 </sub>as per the following reaction is -46.11 kj/ mol at 298 k.
2NH3(g) → N2(g) + 3H2(g)The enthalpy of formation of ammonia describes the following thermochemical equation: <br>1/2 N2 + 3/2 H2 > 2NH3To get the enthalpy change for the given reaction,...
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Assuming enthalpy of combustion of hydrogen at 273 K, –286 kJ and enthalpy of fusion of ice at the same temperature to be + 6.0 kJ, calculate enthalpy change during formation of 100 g of ice
Answer: H2 + 1/2O2 = H2O(l) ΔH (H2) =-286 kJ/mol ΔH H2O (s) = H2O(l) =6.0 kJ/mol n = m/M M (H2O) = 18 g/mol n (H2O) = 100 / 18...
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2Na+Cl2→2NaCl When 10.0 g of Cl2 is used, the reaction produced 12.5 grams NaCl. What is the % yield of the reaction? Use the following molar masses: Cl2=70g/mol and NaCl=58g/mol.
2Na + Cl2 → 2NaClThe theoretical yield of the reaction:m(NaCl) = m(Cl2) × 2 Mr(NaCl) / Mr(Cl2) = 10.0 g × 2 × 58 g/mol / 70 g/mol = 16.6...
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From an initial mix of: 2 mol Cl2, 1 mol Br2, 0.5 mol I2, 0.5 mol Cl−, 1 mol Br−, 2 mol I−; the total quantity of I2 present after all possible reactions occur is
0.5 mol I2 and 0.5 mol Cl- will not react with anything; 2 mol I- will react with one mol of Cl2 producing one mol of I2: 2I- + Cl2...
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A manufacturer would likely make an _______ in a market following the long-run process of beginning and expanding production in response to _______
entry; a sustained pattern of profits
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