1 Answers
Call
Talk Doctor Online in Bissoy App
The standard enthalpy of the reaction: CO(NH2)24) + H20) -› CO2(g) + 2 NHa(a) is -133.42 kJ/mol. Calculate the standard enthalpy of formation of urea, CO(NH2)2(6).
Standard enthalpy of formation=-362kJ/mol
1 Answers 1 views
the standard enthalpy of formation of urea, CO(NH2)2(6). The standard enthalpy of the reaction: CO(NH2)2() + H2Om) -› COz) + 2 NHare) is -133.42 kJ/mol. Calculate
Standard enthalpy of formation=-362kJ/mol
1 Answers 1 views
What is the theoretical yield (in grams) of C9H8O4 when 2.00 g C7H6O3 is heated
with 4.00 g of C4H6O3? If the actual yield is 1.98 g, what is the percent yield?
C7H6O3 + C4H6O3 → C9H8O4 + C2H4O2
C7H6O3 + C4H6O3 rarr; C9H8O4 + C2H4O2 n of C7H6O3 = 2/ (12*7 + 6 + 3*16) = 0.0145 moles this compound is less n of C4H6O3 = 4/(12*4 +...
1 Answers 1 views
6) AgNO3 + K3PO4 Ag3PO4+ KNO3 Mass of AgNO3: 25.0g
Experimental Mass of K3PO4: 9.53g Experimental Yield of Ag3PO4: 18.62g Experiment Yield of KNO3: 13.24g
Molar mass of AgNO3: 169,872 g/mol Molar mass of K3PO4: 212.264 g/mol Molar mass of Ag3PO4: 418.574 g/mol Molar mass of KNO3: 101.102 g/mol. n = m/M n (AgNO3) =...
1 Answers 1 views
combining 0.385 mol of feo3 with excess carbon produced 16.5g of fe.
what is the actual yield of iron in moles?
what was the theoretical yield of iron in moles?
what was the percent yield?
.n (FeO3)=0.385 mol .m (Fe)=16.5 g .n(Fe)theor=? %=? FeO3+ 3C=Fe+3CO .n (Fe)theor= n (FeO3)=0.385 mol Amount of substance of iron n (Fe)=m/Ar= 16.5/56=0.295 mol %= n(Fe)/ n (Fe) theor= 0.295/0.385...
1 Answers 1 views
Titanium can be obtained from it oxide by the reaction shown here. TiO2{s}+ 2 C(s)= Ti(s)+2 CO, 20.0 g Ti are obtained. what is the percent yield for the reaction?
The percent yield calculation: %mas. = m (Ti) practical / m (Ti) theoretical x 100% So if you have 20 g: %mas. = 20 g x 100% / m (Ti)...
1 Answers 1 views
What is unimoleculer reaction, bimolecular reaction, elementary reaction and overall reaction?
A monomolecular reaction is a reaction that occurs with a single molecule. For example, dissociation.A bimolecular reaction is a chemical reaction in which 2 particles (molecules) participate. An elementary reaction...
1 Answers 1 views
What is my actual yield of H2SO4 if I had a theoretical yield of 76 grams of H2SO4 and a percent yield of 79%?
76 x 0.79 = 60.04 g
1 Answers 1 views
In Part A, we saw that the theoretical yield of aluminum oxide is 1.10 mol . Calculate the percent yield if the actual yield of aluminum oxide is 0.803 mol .
Solution:The amount actually produced of a product is the actual yield.Percent yield = Actual yield/Theoretical yield × 100%Percent yield = 0.803mol/1.10mol*100%= 73.0%Answer: Percent yield = 73.0%
1 Answers 1 views
1. If 6.91g are obtained froma reaction of 6.54 g Zn with excess of oxygen.
What is the percent yield of the reaction?
Molar mass: Zn =65.38 g/mol ,0=16.00 g/mol
2Zn+O2--------2ZnOTo calculate the percent yield we must calculate the theoretical yield of ZnO firstUsing a mass-mass relationship,Molar mass of zinc=65.38, but since we have 2 moles it will be 2×65.38=130.76gMolar...
1 Answers 1 views