1 Answers
Call
Talk Doctor Online in Bissoy App
Calculate the root mean square speed of argon molecules in meter per second and kilometers per hour (hint 78.8 gram per mile) at 30C
78.8×303= 23876.4
1 Answers 1 views
An aqueous solution has 18% of solute. By chemical analysis, it was known that it has 10 mol% solute.
What is the molecular weight of the solute?
m = n*M, m - weight, n - quantity of substance, M - molecular weight mx /18 = mH2O / 82nx = nH2O / 9nx *Mx = nH2O * MH2O*18/82Mx...
1 Answers 1 views
1500cm3 of an unknown gas have a pressure of 10000 N/m2 at 30C° find out number of moles of gas present inside the container.
P = 10000 N/m2 = 10000 Pa V = 1500 cm3 = 0.0015 m3n = unknownR = 8.314 m3 Pa K−1 mol−1T = 30°C + 273 = 303 KSolution:The Ideal...
1 Answers 1 views
if i have 100g of coal, 100g of petrol and 100g of wood how much energy (kj) would i get from each?
If you will use the following values of heat of combustion: petrol 45.58 MJ/kg, coal 25.58 MJ/kg and wood 21.14 MJ/kg, you will get the folloving results petrol 4558 kJ,...
1 Answers 1 views
If you cooled copper sulphate saturated solution from 90c to 30c what would happen to the solute in the solution
Answer: The solubility of copper sulphate will decrease. That’s why precipitate CuSO4*5H2O will be formed.
1 Answers 1 views
If you strated with 50 grams of water at 90C and raised the temperature to 110C. Explain how this would support the Law of Conservation or Mass and Energy
At a temperature of 100 degrees Celsius, the water will begin to boil, i.e., form water vapor - go into a gaseous state of aggregation.Moreover, based on the Law of...
1 Answers 1 views
100g of calcium chloride is dissolved in 1L of aqueous solution. Assume solution density of 1.07g/mL. Calculate the molarity, molality, and percent mass of the solution.
n(CaCl2)=m/M=100/111=0.9molemolarity=n(CaCl2)/V(solution)=0.9/1=0.9mole/liter=0.9Mmolality=n(CaCl2)/m(solvent)=0.9/(1·1000·1.07)=8,4·10^-4 mole/gPercent mass=m(CaCl2)/m(solution)=100/(1070+100)=0.085=8.5%
1 Answers 1 views
A solution is prepared by dissolving 20g benzene in 100g carbon tetrachloride. What is the percent by mass of the solution?
a. 17%
b. 20%
c. 83%
d. 500%
Solution.Mass= Mass of C6H6 + Mass of CCl4;Mass = 20g + 100g = 120g;Mass % of benzene = (20/120)×100% =17%;Mass % of carbon tetrachloride = (100/120)×100% = 83%;Answer: a....
1 Answers 1 views
A solution is prepared by dissolving 20g benzene in 100g carbon tetrachloride, what is the % by mass of the solution?
a. 17%
b. 20%
c. 83%
d. 500%
Solution:m(C6H6) = 20 gm(CCl4) = 100 gm(solution) = m(C6H6) + m(CCl4) = 20g + 100g = 120 gw(C6H6) = m(C6H6)/m(solution)*100% = 20g/120g*100% = 17%Answer: 17%
1 Answers 1 views
20g of water dissolve 7.6g of a salt at 25°c.What is the solubility of the salt in g per 100g of water at the same temperature ?
Solubility=[mass of solute/mass of solvent] 100g H20=[7.6/20]100g H20=38g/100g H20
1 Answers 1 views