Analytical Chemistry Calculate the molarity of a 30.0% hydrogen peroxide solution. The reported density of 30% hydrogen peroxide is 1.135 g/cm3. (H2O2 = 34.0147 g/mol)

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Solution:

Assume that the mass of H2O2 solution is 100 g.

Thus:

Mass of H2O2 = (%H2O2 × Mass of solution) / 100% = (30.0% × 100 g) / 100% = 30.0 g

Moles of H2O2 = Mass of H2O2 / Molar mass of H2O2 = 30.0 g / 34.0147 g mol-1 = 0.88197 mol

Solution volume = Mass of solution / Density of solution = 100 g / 1.135 g cm-3 = 88.1057 cm-3

Solution volume = 88.1057 cm-3 = 88.1057 mL = 0.088106 L

Molarity of H2O2 = Moles of H2O2 / Solution volume

Molarity of H2O2 = 0.88197 mol / 0.088106 L = 10.01 mol/L = 10.0 M

Molarity of H2O2 = 10.0 M

OR (short form solution):

(1.135 g soln/1 mL soln) × (30 g H2O2/100 g soln) × (1 mol H2O2/34 g H2O2) × (1000 mL/1 L) = 10.0 M

Answer: The molarity of a 30.0% hydrogen peroxide solution is 10.0 M.

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