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Data Table Molarity of Na2S2O3 0.125 M Initial Buret Reading (Na2S2O3) 1.50 mL Final Buret Reading (Na2S2O3) 14.35 mL Calculate the average molarity of commercial bleach before it was diluted
Molarity of Na2S2O3 0.125 MInitial Buret Reading (Na2S2O3) 1.50 mL.So , MilliMoles of Na2S2O3 = ( 1.50 * 0.125 ).Final Average Concentration = 1.50 * 0.125 / 14.35 = 0.1306620...
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Data Table Molarity of Na2S2O3 0.125 M Initial Buret Reading (Na2S2O3) 1.50 mL Final Buret Reading (Na2S2O3) 14.35 mL Calculate the average molarity of commercial bleach before it was diluted.
average molarity of commercial bleach before it was diluted = 2.11
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What mass of Na2S2O3 is needed to react with 0.12 g of Cl2?
Solution:The balanced chemical equation:Na2S2O3(aq) + 4Cl2(g) + 5H2O(aq) --> 2NaHSO4(aq) + 8HCl(aq)According to the equation: n(Na2S2O3) = n(Cl2)/4Moles of Cl2 = n(Cl2) = Mass of Cl2 / Molar mass of...
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1. Given: 2Al(s) + Fe2O3(s) à Al2O3(s) + 2Fe(l) Step 1 is done!
How many grams of Fe2O3 are needed to produce 6.7 g of Fe?
Step 2: Mass to moles
Step 3: Mole to Mole (Ratio)
Step 4: Mole to Mass
2Al(s) + Fe2O3(s) = Al2O3(s) + 2Fe(l)n=m/MM (Fe) = 55.9 g/molM (Fe2O3) = 159.7 g/moln (Fe)=6.7/55.9 = 0.12 moln (Fe2O3) = 1/2 x n (Fe) = 1/2 x 0.12 =...
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a) What mass of Na2S2O3 is needed to react with 0.12 g of Cl2?
Step 2: Mass to moles
Step 3: Mole to Mole (Ratio)
Step 4: Mole to Mass
Solution:The balanced chemical equation:Na2S2O3(aq) + 4Cl2(g) + 5H2O(aq) --> 2H2SO4(aq) + 6HCl(aq) + 2NaCl(aq)According to the equation: n(Na2S2O3) = n(Cl2)/4Step 1 "Mass of Cl2 to moles of Cl2":Moles of Cl2 =...
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What mass of HCl forms from 2.8 g of Cl2?
Step 2: Mass to moles
Step 3: Mole to Mole (Ratio)
Step 4: Mole to Mass
H2 + Cl2 = 2HClM (Cl2) = 70.9 g/molM (HCl) = 36.5 g/moln (Cl2) = 2.8/70.9 = 0.04 moln (HCl) = 2 x n (Cl2) = 2 x 0.04 =...
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P4 (s) + 5O2 (g) P4O10 (g)
a) What mass of P4O10 forms when 2.7 g of O2 is used?
Step 2: Mass to moles
Step 3: Mole to Mole (Ratio)
Step 4: Mole to Mass
P4 (s) + 5 O2 (g) = P4O10 (g)M (O2) = 32 g/molM (P4O10) = 283.9 g/moln (O2) = 2.7 / 32 = 0.08 moln (P4O10) = 1/5 x n...
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According to the reaction H₂ + Cl₂ → 2HCl the production of 2.0 moles of HCl would require 70. grams of Cl₂. How many grams of H₂ would be needed?
By stoichiometry, you would need 1 mole of H2 to produce 2.0 moles of HClSo you would need (1.0 moles)(2.0 g / mole H2) = 2.0 g
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Chlorine is used by manufacture to bleach cloth.
Na2S2O3 + 4Cl2 + 5H2O 2NaHSO4 + 8 HCl
How many kg of NaHSO4 (120) can be produced from 2.5kg of Na2S2O3(158) and how many kg
of HCl(36.5)?
2.5 kg = 2500 gMoles of Na2S2O3: 2500 g / 158 g/mol = 15.82 molAccording to the equation:Na2S2O3 + 4Cl2 + 5H2O = 2NaHSO4 + 8HClMoles NaHSO4 = 2 moles...
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2 FeCl2 + Cl2 → 2 FeCl3 If 2.4154 moles of FeCl2 are reacted, how many moles of Cl2 will also be reacted?
Solution:The balanced chemical equation:2FeCl2 + Cl2 → 2FeCl3According to the equation above: n(FeCl2)/2 = n(Cl2)Hence,n(Cl2) = n(FeCl2)/2 = 2.4154 mol / 2 = 1.2077 moln(Cl2) = 1.2077 molAnswer: 1.2077 moles of Cl2 will also be...
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