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2 C4H10 + 13 O2 = 8 CO2 + 10 H2O n = V/22.4 n (C4H10) = 0.1/22.4 = 0.0047 mol n (CO2) = 4 · n (C4H10) = 4 · 0.0047 = 0.018 mol V (CO2) = n · 22.4 = 0.018 · 22.4 = 0.403 L = 403 cm3
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