A 0.187 M weak acid solution has a pH of 3.99. Find Ka for the acid. Express your answer using two significant figures.

Md Ariful Islam

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A 0.187 M weak acid solution has a pH of 3.99.

pH of 3.99. = 4 ( approx ) .

[H+] = 10-4 M .

A 0.187 M weak acid solution = C .

CONCENTRATION OF H+ = UNDER ROOT ( C* Ka ) . .

So , Ka = [H+]2 / C . .

So , Ka = 10-8 / 0.187 . = ( 5.347 * 10 -8 ) .( Approx . ) . Answer .........

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