Justify - H*(CO2) = Delta_f H*(CO2) [*means zero in superscript and _f means f in subscript] where, H* is standard enthalpy and Delta_f H* means standard enthalpy change of formation.

Md Ariful Islam

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Md Ariful Islam

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C + O2 --gt; CO2 Delta_f H*(CO2) = H*(CO2) - [H*(C) + H*(O2)] The standard enthalpy of elementary substance is zero: H*(C) = H*(O2) = 0 Therefore Delta_f H*(CO2) = H*(CO2) - [H*(C) + H*(O2)] = H*(CO2) - [0 + 0] = H*(CO2)
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