1. An experiment requires a solution that is 80% methyl alcohol by volume. What volume of methyl alcohol should be added to 200 mL of water to make this solution?

Md Ariful Islam

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Solution:

The percentage of CH3OH by volume is defined as:

ϕCH3OH = [VCH3OH / (VCH3OH + VH2O)] × 100%

Hence,

ϕCH3OH / 100% = VCH3OH / (VCH3OH + VH2O)

80% / 100% = VCH3OH / (VCH3OH + 200 mL)

1.25 × VCH3OH = VCH3OH + 200 mL

0.25 × VCH3OH = 200 mL

VCH3OH = 800 mL

Answer: 800 mL of methyl alcohol (CH3OH) should be added to 200 mL of water to make this solution.

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