write the electron dot formula of:NaOH,N2O,SO2,SO3,SO3--(sulphite ion),sulphate ion,thio sulphate ion,phosphoric acid,phosphate ion,potassium per magnate.

Md Ariful Islam

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Na:O:H the oxygen atom has 2 lone pair e-, 2 e- on top and 2 e- on the bottom of the oxygen atom :N triple bond N - O ::: It is in resonance with 2 other possible structures. O:(:)S::O One of the oxygens shoes a single bond and the other a double. The 2 bonds with oxygen are actually resonant. Sulfur has 2 unpaired electrons. SO3 has 24 electrons. Don't confuse it with sulfite ion, which has 26 electrons. O : S :: O . O : S :: O : : O .O Each oxygen has an octet of electrons. There will be three resonance structures. It will be trigonal planar (no lone pairs on S), with 120 degree bond angles, and have sp2 hybridization. (.O:)2S (: : )2O The element S has 6 valence electrons. Sulfide ion has a -2 charge. That means that sulfide ion has 8 electrons assigned to it. That will fill the valence orbitals of the sulfur atom. O. . . :: . . :S : S :O: . . :: . . O. O::P (:O:H)3 an O::P (:O.)3 K:O:Mn(::O)4
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describe a test to show that potassium sulphite is ionic

The sulfite ion is classified as a member of acidic radicals of the first group in which hydrochloric acid is used as the group reagent. Hydrochloric acid displaces sulfite ions...

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Write the four quantum numbers corresponding to the electron described below: 1. 11th electron in 5f14 2. 8th electron of 4d10 3. 5th electron of 4p6 4. 4th electron of 3p4 5. 11th electron of sodium

1. Principal quantum number N=3,Azimuthal quantum number l=0Magnetic quantum number m=0,Spin quantum number s=+1/22.Principal quantum number n=2Azimuthal quantum number l=1,Magnetic quantum number m=+1 or −1, Spin quantum number s=+21​ or...

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Sulphuric acid reacts with potassium to form potassium sulphate and hydrogen. Determine the mass of potassium sulphate produced if 6.0g of hydrogen wa also formed

2K + H2SO4 = K2SO4 + H2 if m(H2) = 6 g, so n(H2) = 6 g / 2 g/mol = 3 moles; n(H2) : n(K2SO4) = 1 : 1;...

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Calculate the number of mass of phosphoric acid that is produced when 1.45 x1024 molecules of sulfuric acid react with calcium phosphate. Ca3(PO4)2 + 3H2SO4 à 3CaSO4 + 2H3PO4

1 mole of matter contains 6.02214076×10²³ particles.Given number of molecules represents: 1.45 x1024 / 6.02214076×10²³ = 2.4 molesn (H3PO4) = 2/3 n (H2SO4) = 2/3 x 2.4 = 1.6 molesn...

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In the decomposition of phosphoric acid, H3PO4(s), pyrophosphoric acid and water form. How many moles of phosphoric acid are needed to produce 8.34mol of pyrophosphoric acid?

2H3PO4(s) = H2O + H4P2O7According to the equation, 1 mole of pyrophosphoric acid requires 1 mole of phosphoric acid. Therefore, 8.34 moles of pyrophosphoric acid require 8.34 x 2 =...

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If 15.0 mL of phosphoric acid completely neutralizes 38.5 mL of 0.150 mol/L calcium hydroxide, what is the concentration of the phosphoric acid?

2H3PO4 + 3Ca(OH)2 = Ca3PO4 + 6H2OAccording to the equation, n (H3PO4) = 2/3 n (Ca(OH)2).CM = n / Vn (Ca(OH)2) = 0.150 x 0.0385 = 0.006 moln (H3PO4) =...

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How many grams of potassium phosphate will be formed upon the complete reaction of 30.7 grams of phosphoric acid with excess potassium hydroxide

H₃PO₄+3KOH=K₃PO₄+3H₂O 1MolH₃PO₄ -gt; 1Mol K₃PO₄ V(H₃PO₄)=m/M=30.7g/98g/Mol=0.313Mol V(K₃PO₄)=0.313Mol m(K₃PO₄)=V*M=0.313Mol*212g/Mol=66.36g

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calculate the mass of strontium phosphate that forms when 6.25 grams of strontium chloride react with excess phosphoric acid. hydrochloric acid is the other product of this reaction

m(SrCl2)= 6.25g 3SrCl2+ 2H3PO4 = Sr3(PO4)2 + 6HCln(SrCl2)= m(SrCl2)/Mr(SrCl2)= 6.25/(88+35,5*2)=0,039 (mol);n(Sr3(PO4)2)=n(SrCl2)/3=0.013 (mol);m(Sr3(PO4)2)=n(Sr3(PO4)2)*Mr(Sr3(PO4)2)=0.013*454=5.9 (g);Answer: 5.9 g

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You are given the following data. S(s) + 3/2 O2(g) → SO3(g) ΔH = -395.2 kJ 2 SO2(g) + O2(g) → 2 SO3(g) ΔH = -198.2 kJ Calculate ΔH for the reaction below. S(s) + O2(g) → SO2(g)

S(s) + 3/2O2(g) → SO3(g) (I) ΔH1 = -395.2 kJ2SO2(g) + O2(g) → 2SO3(g) (II) ΔH2 = -198.2 kJ(I) – 1/2(II)S(s) + 3/2O2(g) + SO3 → SO2(g) + 1/2O2(g) +...

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When 34.8 gram of potassium sulphate were dissolved in 500cm³ distilled water. Calculate the concentration of potassium sulphate in/litre

34.8 / 174 x 0.5 = 0.4 M.

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