solutionLet the percentage of the isotope 71 Gallium be =y%The percentage of the isotope 69Ga is =(100−y) %Therefore, we write the mass balance equation100×69.72 = y×71+(100−y) ×696972 = 71y+6900−69y2y=6972−6900=72y=36The percentage of the isotope is =36%
1 Answers 1 viewsAverage atomic mass=(19.78%*10.0129amu + 80.22%*11.0093amu)/100%=10.8122amu
1 Answers 1 viewsHence the %abundance of the two isotopes are 20 80 %.
1 Answers 1 viewsAtomic weight for potassium=39.1011amu.
1 Answers 1 viewsSolution:The average atomic mass of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance.Average atomic mass = f1M1 + f2M2 +… + fnMn where...
1 Answers 1 viewsThe number of C-13 atoms equals: N(C13) = (1100 × 1.07 %)/100% = 11.77 ≈ 12 atoms
1 Answers 1 viewsNotice that the abundance of Ag-107 (106.91 amu) is assigned “x” and the Ag-109 (108.90 amu) is “1 – x”. 106.91x + 108.90(1 – x) = 107.87 106.91x + 108.90...
1 Answers 1 viewsThe mass in amu of 2 molecules of Triuranium Octaoxide (U3O8) is 1684 (D).
1 Answers 1 viewsAt first we may designate percentage as parts of 1: B10 content as x and B11 content as y. If there are only two isotopes, so their sum will be...
1 Answers 1 viewsE= mc^2.E=1.66x10-27 x (3 x 10^8)^2=1,494e-10 kJ.
1 Answers 1 views