If the electronic configuration of calcium is [Ar]4s2 then what will be the electronic configuration of chromium and free dispositive mangnese ion ? Explain for 4 marks.

Mass of chromium is equal to 11% of the total mass. Therefore the mass of chromium = 0.11×9.43g=1.033g

The reactivity of Co3+ with NH3 is illustrated showing effective catalysis for N–H dissociation to produce hydrogen applicable for designing ammonia fuel cells.

N(t)=Nо(1/2)^t/1/2tN(t)-remaining amount of substanceN(о)-Initial amount of the substanceN(t)=1/2*133mCi^84/1/2*28N(t)=133*1/2^6N(t)=133*1/64N(t)=133/64N(t)=2,078125 ~~ 2,08

Molar mass of chromium = 51.9961g/mol5.2/51.9961= 0.1Molar mass of oxygen = 15.9995.6/15.999= 0.35= Cr2O7

Potassium ion, Sulfide ion, calcium ion, chloride ion

Chromium (Cr0): [Ar] 3d5 4s1 Free dipositive manganese ion (Mn2+): [Ar] 3d5

The balanced chemical equation for this reaction is shown below:2Al(s) + Cr2O3(s) = 2Cr(s) + Al2O3(s) n(Cr2O3) = 10000g/152g/mol = 65.8 molAccording to the equation n(Al) = n(Cr2O3)*2 = 65.8*2...

A. 1B.2C.3D.2

With increasing amount of sulphate in the solution, less chromium is immobilized in the hydration products. But in the presence of chromate chromium-bearing ettringite-like structure phase is formed first. This...

p=m/V V=m/p = 32000 / 7.14 = 4481.79272 cm3V= a3 a= V^(1/3)= 4481.79272^(1/3) = 16.4873398 cm