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32.00mL of hydrogen gas (at SLC) was generated in the process of HCl reacting with magnesium metal. How many molecules of HCl were required for this reaction?
17.2*1020
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A solution contains 1.569mg of CoSO4(155.0g/mol)per mm. Calculate
a) the volume of 0.007840M EDTA needed to titrated a 25.00mL aliquot of this solution
Mass of sulfate = 0.0001569gSulfate = mass/molar massNumber of moles of cobalt = 0.0001569g/155=0.00000101mol/ml25× 0.00000101= 0.00002525mol
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In a titration, 25.00mL of 0.10mol L-1 sodium hydroxide solution was required to neutralize 12.5 mL of hydrochloric acid. Calculate the concentration of hydrochloric acid.
0.0025mol X mol NaOH + HCl = NaCl + H2O 1 mol 1 moln(NaOH) = C(NaOH) × V(NaOH) = 0.10 mol L-1 × 0.025L = 0.0025 mol.n(HCl) = X mol = 0.0025 mol.C(HCl) =...
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If it requires 75.0 mL of 0.500M NaOH to neutralize 165.0 mL of an HCI solution, what is the concentration of the HCI solution?
Solution:Balanced chemical equation:NaOH + HCl → NaCl + H2OAccording to stoichiometry:n(NaOH) = n(HCl)CM(NaOH) × V(NaOH) = CM(HCl) × V(HCl)Therefore,CM(HCl) = CM(NaOH) × V(NaOH) / V(HCl)CM(HCl) = (0.500 M × 75.0...
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What volume of a 2.00 M HCl solution is required to prepare 200 ml of a 0.500M solution?
Solution: Number of Moles of HCl in solution is: M(HCl) = V(volume)*C(concentration) = 0.2*0.5 = 0.1 (mole); V(HCl) = 0.1 / 2 = 0.05 (liter) = 50 ml; Answer: 50...
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How many mL of concentrated HCL solution are needed to provide 90.0g of HCL? Concentrated HCL solution is 37.0% HCl by weight and has a density of 1.19 g/mL.
p =m/V 1,19 = 90/V V = 75,63 ml - it's volume of 37% HCL Need to solve a mass of full solution ( x = V(HCL)+(H2O) ), then 75,63...
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Calculate the pH in the titration of 10.00mL of 1.0M HCl with 1.0M NaOH after the addition of 0.0mL NaOH?
You're titrating hydrochloric acid, HCl, a strong acid, with sodium hydroxide, NaOH, a strong base, so right from the start you should know that the pH at equivalence point must...
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calculate the molarity of a kcl solution made by adding 15.00ml of distilled water to 48.00ml of 0.75m kcl solution
С(KCl)= n(KCl)/Vsolution;n(KCl)= 0.048*0.75=0.036 mol;Vsolution= 0.048+0.015=0.063 LC(KCl)=0.036/0.063 = 0.57 MAnswer: the molarity of a kcl solution is 0.57 M
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34.62 mL of a 0.3 M Mg(OH)2 solution are needed to neutralize a 15-mL solution of HCl on unknown concentration. Calculate the concentration of HCl solution.
Mg(OH)2+2HCl=MgCl2+2H2O1.Trace by finding the amount of Mg(OH)2. To do this, we multiply the molarity by the volume (liters): 0.03462litres *0.3 mol/litres= 0.010386 mol Mg(OH)22.based on the reaction we find the amount...
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A 0.9030 gram sample of M(OH)2(aq) was mixed with 20.00mL of 2.000M HCl and enough water added to make 100.00mL of solution.
M(OH)2(aq) + 2HCl(aq) ⇨ MCl2(aq) + 2H2O(l)
Moles of HCl added = 0.02000 L x 2.000 M = 0.04000 mole HClMoles of NaOH added to the 10.00 mL aliquot = 0.01764 L x 0.05121 M = 0.000903168Equivalent...
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