1 Answers
What mass of sulfur trioxide is produced from the reaction of 11.4 grams of sulfur dioxide and 3.15 grams of oxygen?
Mass of sulfur trioxide is produced=7.2g
1 Answers 1 views
what product of the combustion of a hydrocarbon occurs only when the supply of oxygen is limited? a. sulfur dioxide b. nitrogen dioxide c. carbon dioxide d. carbon monoxide
c. carbon dioxide
1 Answers 1 views
205 gram hydrogen sulfide reacts with 75.0 g oxygen to produce sulfur and water. Find: a) Gram of sulfur formed b) gram of excess reactant used up c) gram of excess reactant that remained unreacted
H2S + O2 --->>H2O + SMolar mass of H2S = 34.1= 205/34.1 = 6.0112 molesMolar mass of oxygen = 31.99875/31.998 = 2.344 molesMole ratio in both cases = 1:1= 2.344+6.0112...
1 Answers 1 views
methane(CH⁴) burns in oxygen to produce carbon dioxide and water vapor , what is the number of(CH²) MOLECULES produced when 3.2 L of oxygen are comsumed?
Methane(CH4) burns in oxygen to produce carbon dioxide and water vapor.What is the number of (CO2) molecules produced when 3.2 L of oxygen are comsumed?Solution:Calculate the moles of oxygen gas...
1 Answers 1 views
Two atoms of sulfur react with three molecules of oxygen to produce two molecules of sulfur trioxide- write balanced chemical equation
2S + 3O2 2SO3
1 Answers 1 views
According to the following reaction, how many grams of water are required for the complete reaction of 29.0 grams of sulfur dioxide?
sulfur dioxide (g) + water (l) sulfurous acid (H2SO3) (g)
m(SO2) = 29 g M(SO2) = 32 + 16*2 = 64 g/mol n(SO2) = m/M = 29g/64g/mol = 0.453 mol According to the following reaction 1 mol of sulfur dioxide...
1 Answers 1 views
lead (II) sulfide has a composition of 86.6% lead and 13.4% sulfur . if 10.5 g of lead reacts to form lead (II) sulfide . What mass of sulfur reacts?
86.6/201:13.4/32=1:1.PbS.Pb+S=PbS.(10.5/201) x 32= 1.67164179 g of S
1 Answers 1 views
Nitrogen dioxide reacts with water to produce oxygen and ammonia:
4NO2(g)+6H2O(g)→7O2(g)+4NH3(g). How many grams of NH3 can be produced when 4.50 L of NO2 reacts at 435 ∘C and 695 mmHg ?
pV=nRT. n=pV/RT = 695 x 4500 / 62400 x 708= 0,0707912321 moles.0,0707912321 x 17 = 1,20345095 g.
1 Answers 1 views
Pentane (C5H12) burns with oxygen to produce carbon dioxide and water. What mass of
C5H12 is required to produce 450.0 g of CO2? (3 marks)
C5H12(l) + 8O2(g) → 5CO2(g) + 6H2O(l)
M(C5H12) = 72.15 g/mol;M(CO2) = 44.01 g/mol;n=m/M;n(CO2) = 450 g/(44.01 g/mol) = 10.22 moles;Proportion according to the reaction:1 mole (pentane) — 5 moles (CO2)x moles (pentane) — 10.22 moles (CO2)x...
1 Answers 1 views
The complete combustion of heptane (C7H16) in oxygen produces carbon dioxide and water.
If I had 4.75g of heptane and combusted this to completion, how many grams of carbon dioxide would I produce?
100 gm of heptane will form 308 gm of carbon dioxide.So 4.75 gm of heptane will form 14.63 gm of carbon dioxide14.63 gm of CO2 will be produced
1 Answers 1 views