300/1000 = 0.3 LMoles of solute = molarity × Litres of solution= (0.050/ 1L) × 0.3 = 0.015 molMolar Mass = 40.00g/mol= 0.015 × 40.0g/ 1mol = 3.60g = 3.60...
1 Answers 1 viewsStart by pipetting 10.0 ml of 5.01M hydrochloric acid (HC1) into a flask. Add approximately 50 ml of water (remember, not tap water) and three drops of methyl red indicator....
1 Answers 1 viewsMolarity of the solution =2.47M
1 Answers 1 views1) CH3-CH2-CH2-CH3 + Cl2 ---gt; CH3-CH2-CH2-CH2-Cl + HCl CH3-CH2-CH2-CH2-Cl + KOH (dry) --gt; CH3-CH2-CH2=CH2 CH3-CH2-CH2=CH2 + Br2/H2O2 --gt; CH3-CH2-CH2-CH2-Br CH3-CH2-CH2-CH2-Br + KOH (aq) --gt; CH3-CH2-CH2-CH2-OH + KBr CH3-CH2-CH2-CH2-OH + NaBr/H2SO4...
1 Answers 1 views=355mL of 5.0M NaOH stock solution
1 Answers 1 viewsZn2+ + 2e- = ZnE(Zn2+/Zn) = E0(Zn2+/Zn) + R*T/(2*F)*ln([Zn2+]) = -0.763+8.314*298/(2*96500)*ln(0.02) = -0.813 VAnswer: -0.813 V
1 Answers 1 viewsIf you add 0.64 g of solid sodium hydroxide to the stock solution you'll get a 0.2-M solution of (approximately) the same volume.
1 Answers 1 viewsThe dilution coefficient equals:n = c1/c2 = 0.25 mol/L / 0.010 mol/L = 25From here, the volume of the stock solution that must be used is:V1 = V2 / n...
1 Answers 1 viewsChemical equation: HNO2 + NaOH → NaNO2 + H2O The volume of NaOH at the equivalence point equals: V(NaOH) = (C(HNO2)∙V(HNO2))/(C(NaOH)) = (0.10∙0.100)/0.10 = 0.100 (L) At the equivalence point...
1 Answers 1 viewsa. 100mL
1 Answers 1 views