Reaction: Glucose-6-P ----gt; Fructose-6-P 0,5 M 0 x x 0,5 - x x For the following reaction expression of the equilibrium constant is: K=0.67= x/(0.5-x) X = 0.2 n (Fructose-6-P)...
1 Answers 1 viewsC = 100-30= 70 grams
1 Answers 1 viewsGrams of Magnesium Sulphate =163.74g
1 Answers 1 views30.78 g
1 Answers 1 viewsGrams of magnesium oxide=6.05g
1 Answers 1 viewsV1/T1= V2/T25.5/298= 10/T20.0185T2= 10T2= 10/0.0185= 540.54K
1 Answers 1 views[H+] = 0.001341.pH= - log0.001341 = 2.87.
1 Answers 1 views2KClO3=2KCl+3O2Per 1 gram of KCl there are 0.644 g O2 produced.Per 49.2 gram of KCl there are 31.678 g O2 produced.
1 Answers 1 viewsPV = nRT1×65.0 = n× 8.314 J/mol·K×29865= n×2477.572n= 65/2477.572n= 0.026Molar mass of nitrogen = 14.0067= 14.0067×0.026=0.3675g
1 Answers 1 viewsYou can calculate this by such reaction: NH₄NO₃ --gt; N₂ + frac12;O₂ + 2H₂O ==gt; 2NH₄NO₃ --gt; 2N₂ + O₂ + 4H₂O The law of conservation of mass solves this...
1 Answers 1 views