Answered Apr 21, 2024
Heat capacity of metal
= - 31.5 J/5.37 g/(15.5 - 22.0)℃
= 0.902 J/(g℃).
It approximately close to the heat capacity of aluminium. So the metal is aluminium (Al).
Q=mc∆T= 1260 x 0.39 x (280-25)= 127 764 J.
Mass = 7.5 g= 0.0075Kg∆T = 65.1 - 11.2 = 53.9°CSpecific heat capacity of Copper = 386 J/Kg -KQ = Mc∆T= 0.0075 kg × 53.9 °C × 386 j/Kg-K= 156.041...
∆H = m x s x ∆T= 155 × 4.184 × (100-15)= 648.52 × 85= 55124.2J
Q = c*m*(t2-t1) Q(metal) = Q(H2O) Q(H2O) = c(H2O)*m(H2O)*(t2(H2O) ndash; t1(H2O)) = 4.186 * 83 * (58.3 ndash; 26)= 11.2 kJ Q(metal) = c(metal)*m(metal)*(t1(metal) ndash; t2(metal)) = c(metal) * 126...
Q=m*c*(t2-t1) c=Q/(m*(t2-t1))=19.5 kJ / (0.205 kg *(197-56.5)K) = 0.677 kJ/(kg*K)
Answer: Heat of vaporization is the amount of energy required to vaporize 1 g of this substance: Hv = 8720/9.43 = 924.7 J/g
lnp2/p1=-∆Hvap x(1/T2 - 1/T1)/RT2=(lnp2/p1 x R/-∆Hvap) + 1/T1 T2= 3.40886705 .
According to the heat equation:Q = m × c × ∆T = m × c × (T2 - T1)where Q - amount of heat, m - mass, c - specific...
Solution:Density expression:Density = mass / volume = g/mL or g/cm3Therefore,Density of a piece of metal = 12.5 g / 4.25 cm3 = 2.94 g/cm3Answer: The density of a piece of...
c = Q / m * ∆T ∆T = T2 – T1 T2 = t2 + 273.15 = 154.8 °C+ 273.15 = 427.95 K T1 = t1 + 273.15 =...
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