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In first, You must to definite the excess substance in this case. Let's look to given reaction:

CH4 + 4Cl2–>CCl4 + 4HCl

It follows from it, that for 16 g CH4 need to take 4*2*35.5 = 284 g Cl2. This means that there is an excess of CH4. Therefore, it is necessary to calculate by chlorine: 284 g Cl2 --> 35.5*4+12= 154 g CCl4. 2.71 g Cl2 --> 2.71* 154/284 = 1.47 g CCl4.

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