If two individuals with such genotypes are crossed, the number of different genotypes and thus, phenotypes would be enormous. It is not possible to provide the ratio because it requires...
1 Answers 1 viewsAnswer:p = frequency of the B allele becomes 0.7q = frequency of the b allele = 0.3Explanation:Hardy Weinberg equation is used to calculate frequencies.Hardy Weinberg equation can be written as...
1 Answers 1 viewsSolution: The frequencies of different types of genotypes in ideal population are described by the Hardy–Weinberg law: p^2 +2pq+q^2 =1 where p 2 is a frequency of dominant homozygotes, q^2...
1 Answers 1 viewsMother: bb x Father: BbChildren:Genotypes: Bb - 50%; bb - 50%Phenotypes: brown eyes (Bb) - 50%; blue eyes (bb) - 50%.
1 Answers 1 viewsThe dominant trait is a tall, because it manifests itself in both a homozygous and a heterozygous state.
1 Answers 1 viewsAlmond shape eyes - dominant trait, let it be Rround shape eyes - recessive trait, so it will be rThe cross : RR * rrOffspring: Rr (so the phenotype -...
1 Answers 1 viewsGenotype;WW, Ww,Ww,wwPhenotype3short:1long
1 Answers 1 viewsPhenotype: It is the observable trait in an individual because of the genetic makeup for that trait. Like here, the phenotype i.e. the observable trait in the rabbit are floppy...
1 Answers 1 viewsHeterozygous A is AOHeterozygous B is BOPossibilities for offspring are:AO 25%BO 25%AB 25%OO 25%So there is a 25% chance the offspring will be AB and a 25% chance the offspring...
1 Answers 1 viewsParents Genotypes ;The mother dragon is heterozygous for the wing gene (Ww) and the horn gene (Hh). The father is homozygous recessive for the wing gene (ww) and the horn...
1 Answers 1 views