After 5 seconds, the taxi will have a speed of 4/ms^2 x 5 s = 20 m/s. The average speed is 20 m/s / 2 = 10 m/s, because the speed increases from 0 m/s to 20 m/s in a straight line -- in such a case, the average speed is the maximum speed divided by 2. In general, Vavg is the integral of V with respect to t from Vinitial to Vfinal divided by tfinal - tinitial. In this case, V = 4t m/s, so the integral wrt t is 2t^2, which gives 2 x 25 = 50 m, divided by 5 s, = 10 m/s.

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