The thing to remember here is that the equilibrium constant of the forward reaction is always equal to the inverse of the equilibrium constant of the reverse reaction or vice...
1 Answers 1 viewsIf she runs $5"km"$ in half an hour then she could run $10"km"$ in 1 hour. You must assume that she can maintain this speed otherwise the prediction is not...
1 Answers 1 viewsPart 1: determining the distance traveled We are told the return trip took 11 hours at a speed of 10 mph. $"distance" = 11 cancel( " hours") xx (10 "...
1 Answers 1 viewsFirst convert her speed into km/hr. There are 60 min in 1 hr so 5 min = 5/60 = 1/12 of an hour. So her speed will be dist/time =...
1 Answers 1 viewsGiven, $d = 125"km" * (10^3"m")/"km" approx 1.25*10^5"m"$ $t = 2"h" * (3600"s")/"h" approx 7.2*10^3"s"$ Recall, $bars = d/t$ Hence, $bars = d/t approx (17.4"m")/"s"$ is the average speed of...
1 Answers 1 viewsavg. speed=total distance/total time. Therefore add the total distance and divide it by total time. You must also add the time rested as the question asks for avg. speed of...
1 Answers 1 viewsAverage velocity=Total distance travelled / Total time taken In other words $A_(avg)=(distance)/(time)$ Sorry! its total distance and total time So, $rarrA_(avg)=133/3.5=38mph$ $mph=mil$$es$ $per$ $hour$
1 Answers 1 viewsThis is a ratio, also called a quotient, and it is a division problem. To obtain the units desired of km/h you simply divided the given value of kilometers by...
1 Answers 1 viewsWe can use the formula: $"speed" = ("distance")/("time")$ To create two equations we can use to solve this problem. ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ We know that the tourist must reach the...
1 Answers 1 views$sf((a))$ The velocity of the car relative to the train = $sf(90-70=20color(white)(x)"km/hr")$. To pass the train it needs to cover a distance of 1.5 km. $sf(t=d/v=1.5/20=0.075color(white)(x)"hr")$ $sf(t=0.075xx60=4.5color(white)(x)"min")$ $sf((b))$ Relative to...
1 Answers 1 views