Half-life is defined as the amount of time that it takes for radioactive substance to loose half its radioactivity. If a substance has a half life of 58 years and starts with 500 g radioactive, how much remains radioactive after 30 years?

The sample will lose half of its mass after 4 hours. The half life. $ 8/2 = 4$ The sample will lose half of the remaining four after another...

Half life refers to the time it takes or half of the substance to decay. If the half life is 5 years and we begin with 2000 grams, we...

$67" months" = 5.58334" years"$ $"Amount remaining" = "Beginning Amount"/2^n$ Where: $"Beginning Amount"$ is the whole sample (here, $100%$) $n = "elapsed time"/"half-life"$ $:. "% Amount remaining...

A half life is defined as the period of time it takes for half of a radioactive substance to decay. Thus, if a substance has a half life of 4...

Radioactive decay constant ($λ$) $λ = "ln(2)"/("T"_"1/2") = "ln(2)"/"125 years"$ Amount of radioactive substance left after time $t$ is $"N = N"_0 e^-(λt)$ $"N =...

Your strategy here will be to use Avogadro's number to calculate the number of atoms of plutonium-239 that you're starting with. One you know that, use the equation that allows...

Use the equation $N(t)=N_0e^(-lambdat)$ $N_0=$initial amount $=64 g$ The half life is $=t_(1/2)=ln2/lambda$ $t_(1/2)=350 y$ Therefore, $lambda=ln2/350 y^(-1)$ $t=800y$ $N(t)=64*e^((-ln2/350)*800)$ $=13.13g$

The half-life of a substance is the amount of time it takes for half of that substance to decay. However, after two half-lives, half of the half remaining will decay,...

(a) Mass after t years The formula for calculating the amount remaining after a number of half-lives, $n$ is $color(blue)(bar(ul(|color(white)(a/a)"A" = "A"_0/2^ncolor(white)(a/a)|)))" "$ where $"A"_0$ is...

If we start with $150g$ of the isotope, after one half-life the quantity will diminish to $(150g)/2 = 75g$ which is half the original quantity. This can be written...