Sulfide anion is oxidized to sulfur dioxide; dioxygen gas is reduced to oxide anion. This is formally a 6 electron transfer. Is this balanced? How could I remove the non-integral coefficient?
Mass is conserved in every chemical reaction. So, if I start with 10 g of reactant I must finish with 10 g of product. You started with 3.6 g of...
1 Answers 1 views$"Moles of"$ $N_2O$ $=$ $(21.3*g)/(44.02*g*mol^-1)=0.483*mol$ And for stoichiometric reaction we need, $0.483*molxx3/2xx32.00*g*mol^-1=??*g$ $"dioxygen gas"$.
1 Answers 1 viewsWe need a stoichiometic equation: $SO_2(g) + 1/2O_2(g) rarr SO_3(g)$ The equation unequivocally tells us that the reaction of $64*g$ $SO_2(g)$ with $16*g$ $O_2(g)$ gives $80*g$ $SO_3(g)$. The given masses...
1 Answers 1 viewsYou must convert $"grams of S" → "moles of S" → "moles of H"_2"S"$ and then use the Ideal Gas Law to find the temperature of the $"H"_2"S"$. 1....
1 Answers 1 viewsThere are four steps in this problem: Write the balanced chemical equation. Calculate the moles of sulfur. Calculate the moles of H₂S. Use the to calculate the temperature....
1 Answers 1 viewsWe are given the amounts of two reactants, so this is a limiting reactant problem. We know that we will need a balanced equation with volumes of the involved....
1 Answers 1 views$"Dalton's Law of Partial Pressures"$ states UNEQUIVOCALLY that in a gaseous mixture, the partial pressure exerted by a gaseous component is the SAME as it would exert if it ALONE...
1 Answers 1 viewsPbS (aq) $<=>$ $ Pb^(2+)$ (aq) + $ S^(2-)$ (aq) $K_(sp)$ = [ $ Pb^(2+)$ (aq) ] . [ $...
1 Answers 1 views$"8.5 mols of gas"$ Write the reaction: $2"SO"_2(g) + "O"_2(g) -> 2"SO"_3(g)$ For this reaction, you know that the starting mols are: $n_("SO"_2,i) = "5 mols...
1 Answers 1 viewsYou used the so-called $"Mohr's salt"$, which is a stable and convenient source of $"Fe(II) salt"$, i.e. $[(NH_4)_2Fe(SO_4)_2]*6H_2O$. We can ignore the ammonium and sulfate shrubbery, and represent the redox...
1 Answers 1 views