Just use a little . $507g$ $FeCl_2$ / $126.751 g$ $FeCl_2$ = $4 mol$ $FeCl_2$ $4 mol$ $FeCl_2$ x $1 mol$ $Fe(OH)_2$ = $4 mol$ $Fe(OH)_2$ $4 mol$ $Fe(OH)_2$...
1 Answers 1 views1. Write the balanced equation. $"Zn" + "2HCl" → "ZnCl"_2 + "H"_2$ 2. Calculate the moles of $"Zn"$. $"Moles of Zn" = 30.0 color(red)(cancel(color(black)("g Zn"))) × ("1 mol Zn")/(65.38...
1 Answers 1 viewsWe can use to find the moles of $Mg(NO_3)_2$ and then the respective grams of $Mg(NO_3)_2$. If 8 moles of water are produced, we can find out how many moles...
1 Answers 1 viewsYOu have been given the chemical equation: $H_2(g) + Cl_2(g) rarr 2HCl(g)$ There are 2 equiv (moles if you like) of gaseous product, and 2 equiv gaseous reactant. Clearly, mass...
1 Answers 1 views$HCl(aq)+H_2O(l)rarr Cu^(2+) + 2NO_3^-$ $Ca(OH)_2(s) stackrel(H_2O)rarr Ca^(2+) +2HO^-$ $Ca(NO_3)_2(s) stackrel(H_2O)rarr Ca^(2+) +2NO_3^-$ $NH_3(aq) +H_2O(l) rightleftharpoonsNH_4^+ + HO^-$ And one of these things is not like the other ones.........
1 Answers 1 viewsAmmonia is a Bronsted base: $NH_3(aq) + H_2O(l) rightleftharpoons NH_4^+ + OH^-$ $pK_b = 4.75$ I am not going to solve this equation using $pK_b$, but most of the ammonia...
1 Answers 1 viewsThe standard of formation is the enthalpy associated with the formation of 1 mole of substance from its constituent in their standard states under specified conditions. And of course...
1 Answers 1 viewsAnd I don't know offhand how they measured the enthalpy change for the reaction, $H_2(g)+Cl_2(g)rarr2HCl(g)+Delta$ but such a measurement could conceivably be done and no doubt has been done....
1 Answers 1 viewsIn its oxides, an oxidation number of $-II$ is typical. And since, for neutral , the sum of the is $0$. For $"ferrous oxide"$ we have $Fe^(+II)O^(-II)$; and for $"ferric...
1 Answers 1 viewsIn this reaction Fe is being oxidized and H is being reduced. To check the balance of a redox reaction, make sure that the number of electrons exchanged are equal...
1 Answers 1 views