Oxygen always has an oxidation number of
When
You can also check this because
Where $N_A="Avogadro's number"$ $=$ $6.022xx10^23*mol^-1$ $"Number of moles"$ $=$ $"Mass"/"Molar mass"$ $=$ $(27*g)/(54.00*g*mol^-1)=0.500*mol$ And thus $"Number of molecules"$ $=$ $6.022xx10^23*mol^-1$ $=$ $3.011xx10^23$ $OF_2$ molecules.......... What is the oxdation number of...
1 Answers 1 viewsAnd $"cobalt(III) oxide"$, $Co_2O_3$.....$"cobaltic oxide"$. And a mixed oxidation state oxide exists, $Co_3O_4$ (note that I simply added the given formulae together, $"cobalt(II,III) oxide"$).
1 Answers 1 viewsWe can use the to calculate the partial pressures. $color(blue)(bar(ul(|color(white)(a/a)pV = nRTcolor(white)(a/a)|)))" "$ or $p = (nRT)/V$ The number of moles $n$...
1 Answers 1 viewsMass is a measure of the number of particles. Here you have $O$ atoms, and dioxygen, $O_2$, and ozone molecules, $O_3$ but each have the same mass by specification. There...
1 Answers 1 viewsIn its oxides, an oxidation number of $-II$ is typical. And since, for neutral , the sum of the is $0$. For $"ferrous oxide"$ we have $Fe^(+II)O^(-II)$; and for $"ferric...
1 Answers 1 views$"Oxidation/state"$ number is the charge left on the atom of interest, when all the pairs of electrons are broken with the charge assigned to the most electronegative atom. See...
1 Answers 1 viewsFor starters, you should know that chromium has an oxidation number equal to $+6$ in the dichromate anion. The two most common oxidation states for chromium are $+6$ and $+3$,...
1 Answers 1 viewsI have got the rules from elsewhere: $1.$ $"The oxidation number of a free element is always 0."$ $2.$ $"The oxidation number of a mono-atomic ion is equal"$ $"to the...
1 Answers 1 viewsAnd for oxides, the oxygen state of the oxygen is necessarily $-II$.. And we assign the oxidation state of the heteroatom on this basis.... $SO_2$, we gots $S(+IV)$; $SO_3$, we...
1 Answers 1 viewsJust to expand on the subject of oxidation of alcohols, the method of oxidation number, and gain or loss of electrons, can be utilized in the scenario, provided that we...
1 Answers 1 views