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The $K_"sp"$ values are of course available in the literature, and SHOULD have been included in the question.

Once we have $K_"sp"$ values, then we can address the various solubility. For calcium chloride we approach this in this manner........

$Ca(OH)_2(s) rightleftharpoons Ca^(2+)+2HO^-$

Now $K_"sp"=[Ca^(2+)][HO^-]^2$.

And if we call the solubility of calcium chloride, $S$, then $S=[Ca^(2+)]$, and $[Cl^-]=2S$ (provided there is no extraneous source of calcium and chloride ions......)

So $K_"sp"=Sxx(2S)^2=4S^3$.

And $S=""^3sqrt((K_"sp")/4)$.

And so without $K_"sp"$ we are at an impasse. Such calculations require prior measurement or reference to the literature data.

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