It will give a weakly acidic solution. We could calculate $H_3O^+$, and $NO_2^-$, and $[HO^-]$ if we were given $K_a$ for this weak acid. Of course, I could look it up, but then so could you.
The $"mole"$, $N_A$, is simply a number. Admittedly, it is a very large number, $N_A=6.022xx10^23*mol^-1$. And if you have a mole of stuff, you have $6.022xx10^23$ INDIVIDUAL ITEMS of that...
We can solve this problem using some calculations: $"molarity" = "mol solute"/"L soln"$ We should convert the given mass of $"(NH"_4")"_2"SO"_4$ to moles using its molar mass (calculated to...
You don't actually need to know the molecular formula for lactic acid in order to solve this problem. You are told that lactic acid has one acidic proton, which...
Strong acids (and hydrochloric acid is a strong acid), are almost completely ionized in water: $HCl(aq) + H_2O(l) rarr H_3O^+ + Cl^-$ And thus a $0.500*mol*L^-1$ solution of $HCl(aq)$ is...
These are mostly straightforward, except for one. $"Al"("NO"_3)_3$ is strongly acidic because $"Al"^(3+)$ is a Lewis acid. It has an empty $3p_z$ orbital that accepts electron , making it...
Both $H_2SO_4$ and $HNO_3$ contain hydroxides....and yet these are STRONG acids.... And an acid is typically the hydroxide of a non-metal, whereas a base is typically the hydroxide of a...
The metal in the higher oxidation state is the reducing agent.......the electron pair acceptor: And of course, these species could be reduced to give the bivalent metal ion.......... $SnX_4 +2e^(-)...
