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It will behave a base in water. Acetate salts undergo the following equilibrium in water:

$H_3C-CO_2^(-) + H_2O(l) rightleftharpoons H_3C-CO_2H + HO^-$

Given a $pK_a$ for acetic acid (which I think is $4.76$) you could quantify this expression. Anyway an aqueous solution of rubidium acetate will be slightly basic given the hydrolysis reaction.

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