The first thing you need to do here is to figure out the of the solution,
$color(blue)(ul(color(black)(rho = m/V)))$
In your case, you will have
$rho = "5.20 g"/"5.00 mL" = "1.04 g mL"^(-1)$
Now, the key thing to keep in mind here is that are homogeneous , which implies that they have the same composition throughout.
This allows you to use the known composition of the initial solution, which contains
$1.00 color(red)(cancel(color(black)("g KCl"))) * overbrace("5.00 mL solution"/(0.26color(red)(cancel(color(black)("g KCl")))))^(color(blue)("the known composition of the solution")) = "19.23 mL solution"$
Finally, use the density of the solution to convert the volume to mass
$19.23 color(red)(cancel(color(black)("mL solution"))) * overbrace("1.04 g"/(1color(red)(cancel(color(black)("mL solution")))))^(color(blue)("= 1.04 g mL"^(-1))) = color(darkgreen)(ul(color(black)("20. g")))$
The answer is rounded to two , the number of sig figs you have for the mass of potassium chloride.