What molar quantity of magnesium ion is present in a $1000*mL$ volume of $0.50*mol*L^-1$ $MgSO_4(aq)$?

Md Ariful Islam

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Md Ariful Islam

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You specify a $0.5*mol*L^-1$ solution of $MgSO_4(aq)$.

Since $"Concentration"$ $=$ $"Moles of solute"/"Volume of solution"$,

$"Moles of solute"="Concentration"xx"Volume of solution"$.

If we have a $1000*mL$ volume, then.......

$"Moles of solute"$

$0.5*mol*cancel(L^-1)xx1000*cancel(mL)xx10^-3cancel(L)*cancel(mL^-1)=0.5*mol " with respect to " Mg^(2+)(aq)$.

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