A 25.0 mL sample of sulfuric acid is completely neutralized by 32.8 mL of 0.116 mol/L ammonia solution. Ammonium sulfate is formed What is the concentration of the sulfuric acid?

Md Ariful Islam

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Md Ariful Islam

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We need (i) a stroichiometric equation:

$H_2SO_4(aq) + 2NH_3(aq) rarr 2NH_4^+ + SO_4^(2-)$

At the 2nd equivalence point, the solution will stoichiometric in $"ammonium sulfate"$. An appropriate indicator must be used.

And (ii) a calculation,

$[H_2SO_4]=1/2xx(32.8xx10^-3*Lxx0.116*mol*L^-1)/(25.0xx10^-3*L)$

$=??*mol*L^-1$

Why did we use a $1/2$ factor in the calculation?

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