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And in Scotland (where there are notable dipsos!) it is $50*mg" per 100"$ $mL$ of blood.

And thus is molar terms, we simply turn the mass into a molar quantity:

$"Molarity"$ $=$ $"Moles of solute"/"Volume of solution"$

$=$ $(80*cancel(mg)xx10^-3*cancel(g)*cancel(mg^-1))/(46*cancel(g)*mol^-1)xx1/(100*cancel(mL)xx10^-3*L*cancel(mL^-1))$

$=$ $0.017*mol*L^-1$ in England.

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